Coordinate Geometry – NCERT Solutions for Class 9

NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry is provided here to help students obtain higher marks in their exams. The solutions are explained in a step-by-step manner for better clarity and development of the basics in the students. The experts at SimplyAcad have reviewed all the answers to ensure maximum support for the students. Go below to get the solutions of all the exercises in your NCERT maths textbooks.

Overview of the Exercises of NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry

Exercise 3.1: The first exercise deals with introducing the basic concepts of coordinate geometry including Cartesian plane, quadrants, coordinates of points, distance formula, and the section formula.

Exercise 3.2: The second exercise revolves around the different forms of equations of a straight line. Finding the slope and intercept of a line is also focused.

NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.1

Question 1: How will you describe the position of a table lamp on your study table to another person?

Solution:

To describe the position of a table lamp on the study table, we have to take two lines, a perpendicular and horizontal on the table.

Considering the table as a plane and taking the perpendicular line as Y-axis and horizontal as X-axis.

Take one corner of the table as origin where both X and Y axes intersect each other.

Now, the length of the table is X-axis and breadth is Y-axis. The red dot indicates a lamp.

Measure the distance of this point from both X and Y axes and then write it in terms of coordinates.

Let the distance of the point from Y-axis be ‘x’ and from X-axis be ‘y’.

Then the position of the table lamp in terms of coordinates is (x,y).

Question 2: (Street Plan) : A city has two main roads which cross each other at the centre of the city. These two roads are along the North-South direction and East-West direction.

All the other streets of the city run parallel to these roads and are 200 m apart. There are 5 streets in each direction. Using 1cm = 200 m, draw a model of the city on your notebook. Represent the roads/streets by single lines. There are many cross- streets in your model. A particular cross-street is made by two streets, one running in the North-South direction and another in the East-West direction. Each cross street is referred to in the following manner: If the 2nd street running in the North-South direction and 5th in the East-West direction meet at some crossing, then we will call this cross-street (2, 5). Using this convention, find:

(i) how many cross-streets can be referred to as (4, 3)?

(ii) how many cross-streets can be referred to as (3, 4)?

Solution:

(i)

From the figure; It can be observed that,

only one cross street can be referred to as (4, 3).

(ii)

From the figure; It can be observed that,

Only one cross street can be referred to as (3, 4).

NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.2

Question 1: Write the answer of each of the following

(i) What is the name of horizontal and the vertical lines drawn to determine the position of any point in the Cartesian plane?

(ii) What is the name of each part of the plane formed by x-axis and y-axis?

(iII) Write the name of the point where x-axis and y-axis intersect.

Solution:

(i) The name of horizontal lines and vertical lines drawn to determine the position of any point in the Cartesian plane is x-axis and y-axis respectively.

The Cartesian plane has 4 quadrants.

(ii) The name of each part of the plane formed by x-axis and the y-axis is ‘Quadrant’.

The Cartesian plane has 4 quadrants.

(iii) The point where these two lines intersect is called origin.

Question 2: See Fig.3.14, and write the following:

(i) Write the coordinates of B.

(ii) Write the coordinates of C.

(iii) Write the point identified by the coordinates (-3, -5).

(iv) The point identified by the coordinates $(2,-4)$.

(v) The abscissa of the point $\mathrm{D}$.

(vi) The ordinate of the point $\mathrm{H}$.

(vii) The coordinates of the point $\mathrm{L}$.

(viii) The coordinates of the point $\mathrm{M}$.

Solution:

(i) The point B is 5 units to the left of Y-axis and 2 units above X-axis.

Therefore, the coordinates of B is (-5, 2).

(ii) The point C is 5 units to the right of Y-axis and 5 units below X-axis.

Therefore, the coordinates of C is (5, -5).

(iii) The point E is 3 units to the left of Y-axis and 5 units below X-axis.

Therefore, the point identified by the coordinates (-3, -5) is E.

(iv) The point G is 2 units to the right of Y-axis and 4 units below X-axis.

Therefore, the point identified by the coordinates (2, -4) is G.

(v) Abscissa of the point D means x coordinate of the point D.

So, abscissa of the point D is 6.

(vi) Ordinate of point H means y coordinate of point H.

So, the ordinate of point H is -3.

(vii) The point L is on the Y-axis. Its x-coordinate will be zero.

The coordinates of the point L is (0, 5).

(viii) The point M is on the X-axis. Its y-coordinate will be zero.

The coordinates of the point M is (- 3, 0).